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Mathematics 18 Online
OpenStudy (anonymous):

find the limit: lim as x approaches -infinity, (e^x-e^-x)/(e^x+e^-x)

OpenStudy (anonymous):

are you factoring something there myininaya ? :)

OpenStudy (jamesj):

Divide top and bottom by e^-x and you have \[(e^{2x}-1)/(e^{2x}+1)\] Now the limit as x -> -inf of the numerator and denominator is finite and non-zero. Namely, -1/1 hence the limit is -1.

OpenStudy (jamesj):

By the way, dividing by e^-x is the same as multiplying by e^x, which is perhaps slightly more intuitive.

OpenStudy (anonymous):

why do you divide by e^-x? I thought the numerator and denominator were set as they are and cant be manipulated?

OpenStudy (anonymous):

i got -1

OpenStudy (jamesj):

Of course we can manipulate fractions. For example look at 1/2. Multiply top and bottom by 2 and you get 2/4. This is in principle identical to what we just did.

OpenStudy (anonymous):

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