Question

solve for x
49^(3x+1)=7^((x^2)+16x+18)

Answer 1

(3x+1)ln(49)=(x^2+16x+18)ln(7)
since ln(7)^2=ln(49)
using this 2ln(7)=ln(49)
2(3x+1)ln(7)=(x^2+16x+18)ln(7)
the ln(7) cancel
leaving
6x+2=x^2+16x+18
0=x^2+10x+16
(x+8)(x+2)=0
x=-8
x=-2

Answer 2

using the rule of ln is this
ln(x)^n=nln(x) thats why i brought down everything to the front of the (ln) in case you were curious