Question

See attached picture

Answer 1

why?

Answer 2

Because it's too hard to type out

Answer 3

\[\frac{2}{49z^3y}-\frac{1}{14z^2y}\]

Answer 4

use
\[98z^3y\] as your denominator

Answer 5

so get
\[\frac{4}{98z^3y}-\frac{7z}{98z^3y}\]

Answer 6

I see what I did wrong. I had 98z^3y

Answer 7

with 4-7z over 98z^2y still isnt the right answer

Answer 8

should be
\[\frac{4-7z}{98z^3y}\] not over
\[98z^2y\]

Answer 9

How did you get z on the 7?