solve by elimination x-y+z=-1 x+y+3z=-3 2x-y+2z=0
are you sdoing matrices?
no its umm systems
alright so with systems you know the 3 rules you can do right?
elimination subsitution
what you want to do in this case is take equation 1 and 3 and try to eliminate a variable by adding them together
ok
and then take 1 and 2 and try to get them to cancel the same variable
ok
soo 3x-2y+3z=-1
not quite,alright so you have equation 1 and 2 x-y+z=-1 x+y+3z=-3 when dealing with systems you can add two equations and replace it with the row equation you are adding them with so if you were to add equation one with 2 you'd get x-y+z=-1 2x+4z=-4 2x-y+2z=0
see how it cancels a variable y out?
oh yea ok
so what would why equal though?
once you cancel the y variable in another equation you'll be able to get one variable and then find the others by using the equations you started with
ok
your answers should be (x,y,z)=(4,2,-3)
do you understand... i might be able to post a screen shot of my work if you want?
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