Question

Why isn't a number with -ve exponent isn't a Polynomial?

Answer 1

because v is a variable?

Answer 2

double negative sentence

Answer 3

har har

Answer 4

Because polynomials are in the form \[\Large a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_2x^2+a_1x^1+a_0x^0\] where n is a positive integer

Answer 5

it does not follow the definintion of polynomial

Answer 6

so what's the defination?

Answer 7

definition*

Answer 8

definition of polynomial
add subtract and raise to non-negative powers

Answer 9

the definition is stated above

Answer 10

exactly

Answer 11

Who's the fastest calculator/computer? Myininaya or Jim Thompson?

Answer 12

jim, can you please explain that?

Answer 13

jim

Answer 14

Yeah, it's jim.

Answer 15

where n is a positive integer and
n>n-1>n-2>....>...

Answer 16

plus jim thompson writes better novels. pop 1280 among the best

Answer 17

a monomial is simply a coefficient times a power of x (where the power is some whole number)


a polynomial is the sum of a collection of monomials

Answer 18

That answer should get more GOOD ANSWER^

Answer 19

polynomials contain variables to constant powers.

For example:

\[X^{6}+X^{2}+X^{100}+X^{3}\]
Constants to variable powers are NOT polynomials

For example,

\[2^{X}+2^{4X}+2^{Y}\]
is NOT a polynomial.

a number with "-ve" as an exponent is not a polynomial because "v" is a variable.

Answer 20

he meant -ve as "negative", never seen that shorthand, but I'm sure it'll catch on someday....

Answer 21

lol.

Answer 22

Thanks Helpers! :)

Answer 23

never saw -ve before saifoo
maybe he invented it?

Answer 24

Haha, that is just to clear any confusion b/w a negative and a hyphen.

Answer 25

maybe....he does have an evil intel chip....

Answer 26

If "-ve" was supposed to mean "negative", then a number to a negative power is not a polynomial because a number is not a variable. i.e. the base must be a variable and not a number for something to be a polynomial.

Answer 27

lol.

Answer 28

No Jim, you do

Answer 29

nope, amd...a dyslexic dam

Answer 30

1/x^2

is that a Monomial?

Answer 31

no, a monomial is in the form \[\LARGE cx^n\] where 'c' is any real number and n is some nonnegative integer

Answer 32

means, n is also a real number?

Answer 33

but 1/x^2 = x^(-2), which violates that definition

Answer 34

n is real, but more specifically (and restrictively), n is a nonnegative integer

Answer 35

n = 0, 1, 2, 3, 4, ....

Answer 36

Alright. thanks Jimmy Neutron! :D