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How do I take the derivative of (integral(e^-s^2 ds) from 0 to t?
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Do you know the fundamental theorem of calculus?
would it simply be e^(-s^2)?
Yes indeed.
Okay good thanks just reviewing
but wait you don't take 0 or t into account?
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the integration from 0 to t I meant
No. The Theorem says (minus some technicalities) the following. Let F(x) be the function \[F(x) = \int\limits_{a}^{x} f(t) \ dt\] for some function f. Then the derivative of F exists and \[\frac{dF}{dx}(x) = f(x)\] Notice that this result is completely independent of a.
You need to use the second fundamental theorem of calculus
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