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Calculate a line integral: xydS where the curve is given with |x| + |y| = 1
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\[\int\limits_{?}^{?} xy dS\] |x| + |y| = 1
c'mon nikvist. :D
So the result is zero?
yes
Was it necessary to get the parametric equation out of this?
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I'm trying to understand line integrals that's why I asked the queastion.
my mistake, the answer is not correct
oh man. well you got a medal. :)
The answer is zero, by symmetry arguments. The path |x| + |y| = 1 is a diamond around the origin. Consider this path in each quadrant.The first quadrant integral cancels the second quadrant as for every xy ds in Q1 has an equal and opposite -xy ds in Q2 (as x -> -x). The same can be said for Q3 and Q4.
Is this correct?
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