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Mathematics 16 Online
OpenStudy (anonymous):

Calculate a line integral: xydS where the curve is given with |x| + |y| = 1

OpenStudy (anonymous):

\[\int\limits_{?}^{?} xy dS\] |x| + |y| = 1

OpenStudy (anonymous):

c'mon nikvist. :D

OpenStudy (anonymous):

So the result is zero?

OpenStudy (nikvist):

yes

OpenStudy (anonymous):

Was it necessary to get the parametric equation out of this?

OpenStudy (anonymous):

I'm trying to understand line integrals that's why I asked the queastion.

OpenStudy (nikvist):

my mistake, the answer is not correct

OpenStudy (anonymous):

oh man. well you got a medal. :)

OpenStudy (jamesj):

The answer is zero, by symmetry arguments. The path |x| + |y| = 1 is a diamond around the origin. Consider this path in each quadrant.The first quadrant integral cancels the second quadrant as for every xy ds in Q1 has an equal and opposite -xy ds in Q2 (as x -> -x). The same can be said for Q3 and Q4.

OpenStudy (anonymous):

Is this correct?

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