Question

A particle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second. What is the maximum height of the particle?

128 feet

224 feet

272 feet

484 feet

Answer 1

Use the formula:
\[v^2=u^2+2as\]solving for s. (v is the velocity at the maximum height [which must be 0], u is the initial velocity [144f/s], a is the acceleration due to gravity [I don't know what this is in imperial units, it's probably in your textbook], and s is the displacement the particle goes through during this movement [remember that you have to add 160 feet to this value])

Good luck!

Answer 2

I dont know the other things im doing virtual school can U solve it and show me how u did it>?

Answer 3

v is 0, since the particle will be at maximum height when it won't go upwards anymore.
u is 144 feet per second (the question tells you this).
a is 32.174 feet per second squared (so says wikipedia!)
s is what you're looking for.

With these, all you need to do is algebra!