Question

integrate 1/((x-3)^2 +1)

Answer 1

i sorta know how to do it but I'm not sure why theres a negative in front of the tan^-1

Answer 2

\[\int\frac{1}{(x-3)^2+1} dx\]

?

Answer 3

yeah thats it

Answer 4

u sub is the way to go

u= x-3

du= dx

\[\int\frac{1}{u^2+1} du\]

Answer 5

yep got that far but I'm missing a negative sign infront of my answer lol

Answer 6

we know this is equal to

\[arctan(u)+C\]

Answer 7

u=x-3

hence

our answer is

\[arctan(x-3)+C\]

Answer 8

there is a negative sign in front of it in the answers

Answer 9

\[-arctan(3-x)=arctan(x-3)\]

Answer 10

oh yeah lol thats right my bad i ended up with the right answer. thanks:)

Answer 11

http://www.wolframalpha.com/input/?i=-arctan%283-x%29%3D+arctan%28x-3%29