Consult Multiple-Concept Example 5 in preparation for this problem. The velocity of a diver just before hitting the water is -10.5 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 1.17 s of the dive?
Your using the equation velocity= displacement/time and you want to get displacement by itself by multiplying time to BOTH sides. by plugging in the numbers you'll get \[time(-10.5 m/s = displacement \div 1.17 s)\] so 1.17s moves to the other side so the equation would just look like \[(-10.5 m/s)(1.17s)= -12.285\]
I have been trying to divide this entire time. I did not realize that if I move displacement over that I would change my division to multiplication. Also, the book is showing me all kinds of crazy stuff to do. Thank you for helping me out.
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