The doorsill of a campus building is h = 8 feet above ground level. To allow wheelchair access, the steps in front of the door are to be replaced by a straight ramp with constant slope 1/10, as shown in the figure. How long must the ramp be
every ten it goes up one so must be 80 feet
it said in the question that the answer is not 80 feet
Think in terms of drawing a triangle on a graph y = 8 Your slope is 1/10. This means every time you move down one unit, you move to the right 10 units. By the time you reach y = 0, you will have reached x = 80. So now use the Pythagorean Theorem -- a^2 + b^2 = c^2 where your "y" term is "a" (leg 1 of the triangle) your "x" term is "b" (leg 2 of the triangle) and "c" is the length of the ramp (the hypotenuse of the triangle) (8)^2 + (80)^2 = c^2 6464 = c^2 80.4 = c |dw:1316488624972:dw|
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