Question

Find the equation of the plane through the point P = (2, 3, 2) and parallel to the plane −(x+4y+z)=2.

Answer 1

parallel planes have parallel normals right?

Answer 2

correct

Answer 3

steal the normal from the other one and use it on the point given

Answer 4

so <-1, 4, 1> for the normal vector?

Answer 5

oops...<-1,-4,-1>

Answer 6

<1,4,1> looks to suffice

Answer 7

even with the negative out front?

Answer 8

yep, the negative is a scalar

Answer 9

it could just as easily be 6 out front

Answer 10

okay...so then it goes to (x-2) +4(y-3) + (z-2) = 0?

Answer 11

looks good to me, simplify as form dictates

Answer 12

x - 2 +4y - 12 + z - 2

x+4y + z = -16

Answer 13

x + y + z = -4?

Answer 14

(x-2) +4(y-3) + (z-2) = 0

x + 4y +z -2-12-2 = 0

x + 4y +z -16 = 0 , is good

Answer 15

i have to give it as z = again

Answer 16

then put it all to the right but z :)

Answer 17

z = -x -4y +16?

Answer 18

z = 16 -4y -x

Answer 19

excellent...thanx again

Answer 20

youre welcome