Question

y=(x^2-9) all over (x+2) shifted 4 units to the left. Whats the new equation

Answer 1

add 4 to each x part

Answer 2

I did that, and theanswer i got did not shift it 4 units to the left.

Answer 3

\[y=\frac{((x+4)^2-9)}{((x+4)+2)}\]

Answer 4

that is how you move left and right, you modify the x part directly

Answer 5

to move left; go positive; to move right, go negative :)

Answer 6

I got to that step, than i factored the x+4 but i still got some wierd answer

Answer 7

keep an eye on your simplification; thats whatll get ya.

Answer 8

\[y=\frac{(x^2+8x+16-9)}{(x+6)}\]
\[y=\frac{(x^2+8x+7)}{(x+6)}\]
\[y=\frac{(x+7)(x+1)}{(x+6)}\]

Answer 9

Thank you soo much (: but now, on this other problem im givin a point (-4,-6) and its telling me to determine the location of the corresponding point based on the tranformation. y=.5f(x)

Answer 10

is that a: .5 ?

Answer 11

\[\Large .5\ ?\]

Answer 12

0.5
yes.

Answer 13

think of it like this:

(x, f(x))

(-4,-6)
*.5
-------
(-4,-3) .... is the best i can make of that

Answer 14

in other words, modify that y component by a multiple of 0.5

Answer 15

but then what would y=f(0.5x) be? multiply the x by .5 or?

Answer 16

if its inside the () .. your playing with the "x"

if its outside the () ... your playing with the "y"

Answer 17

the trick with this tho is that you have no idea how the function "f" uses the x to make a y value; so modifying the x like that is rather spurious

Answer 18

if htere is material that goes with it, id refer yo to it for the specifics :)

Answer 19

noo, there is just a few problems that he showed uus how to do, hes not a very good teacher :/

Answer 20

then im also haing aloot of trouble with constucting functions :/

Answer 21

a function is just making something that will take an input and give you an output .... whats the hard part for you?

Answer 22

for example....

Answer 23

a wire of length x is bent into the shape of a square. A) express the perimeter of the square as a function of x

Answer 24

B) express the area of the square as a functio0n of x.

Answer 25

if you take a length of x and bend it; and add up all the sides ... you still have x :)

if i take a 12inch coathanger and bend it; i havent changed the length have i?

Answer 26

P(x) = x is what id say for the perimeter

Answer 27

since a square has 4 equal sides; or (1/4)x per side; we should be aware that aware is equal to side*side

Answer 28

A(x) = [(1/4)x]^2 .. right?

Answer 29

ahh i wish i was smart like you :/ hahaha

Answer 30

:) just old

Answer 31

ah, its cause i've missed afew days of school, so now im really behind, espexcially in math:/

Answer 32

good luck with it :)

Answer 33

\[y=2\sqrt[3]{x-1}+5\] with vvertical compression factor of 1/2?
i know you multiply the function by 1/2 but the algebra is messing me up :/

Answer 34

\[y=\ 2\sqrt[3]{x-1}+5\]

\[y=\ \frac{1}{2}(2\sqrt[3]{x-1}+5)\]

\[y=\ \sqrt[3]{x-1}+\frac{5}{2}\]