Question

f(x,y)=e^(sinx)+(x^5)y+ln(1+y^2) find fx and fy

Answer 1

f(x,y)=e^(sinx)+(x^5)y+ln(1+y^2)

fx = cos(x) e^(sin(x)) + 5x^4 y

fy = x^5 +2y/(1+y^2)

if i see it right

Answer 2

\[f(x,y)=e^sinx +x^5y +\ln(1+y^2)\]

Answer 3

that's what it looks like, is that the way you saw it?

Answer 4

enclose exponents in {} to keep it together

Answer 5

\begin{array}c
f(x,y)=e^{sinx}+x^5\ y+ln(1+y^2)\\\\
fx = cos(x) e^{sin(x)} + 5x^4\ y \\\\
fy = x^5 +\frac{2y}{(1+y^2)} \\\\
\end{array}

Answer 6

when doing partials; say like Fx, anything without an "x" is consider constant and is treated as such

Answer 7

Fy same thing; treat everything that is not a y as a constant

Answer 8

thank you so much :)

Answer 9

youre welcome