Question

messed up on the last one...
Solve for x and check. Enter only a number.
3(base 2x) = 27

Answer 1

The problem is \[\Large 3_{2x}=27\] ???

Answer 2

I DONT KNOW

Answer 3

the 2x is up high instead of down low. Maybe I'm writing it wrong.

Answer 4

\[\Large 3^{2x}=27\] ???

Answer 5

yeah, it looks like that

Answer 6

\[\Large 3^{2x}=27\]


\[\Large 3^{2x}=3^3\]
Since the bases are equal (to 3), the exponents are equal


So \[\Large 2x = 3\]Now solve for x



\[\Large 2x = 3\]



\[\Large x = \frac{3}{2}\]

Answer 7

thanks :)