Can't figure out how to factor this x ^{3} - x^{2} - 25x +25
\[x ^{3} - x^{2} - 25x +25 \]
(x^(2))/(3)-(x^(2))/(2)-25x+25 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 6. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. -(x^(2))/(2)*(3)/(3)+(x^(2))/(3)*(2)/(2)-25x+25 Complete the multiplication to produce a denominator of 6 in each expression. -(3x^(2))/(6)+(2x^(2))/(6)-25x+25 Combine the numerators of all expressions that have common denominators. (-3x^(2)+2x^(2))/(6)-25x+25 Combine all like terms in the numerator. (-x^(2))/(6)-25x+25 Move the minus sign from the numerator to the front of the expression. -(x^(2))/(6)-25x+25
? there is no fraction ?
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