Consider the reaction: 3A +5B + 1C --> 2D + 1E If you have 6 moles of reactant A and excess of B and C, how much product E would be formed? Show work so I can understand please.
Since B and C are in excess you don't need to take them into consideration. Using the balanced equation given we can see that the mole ratio of A:E is 3:1. Now you use that ratio and apply it. So \[6A (1E/3A) = 2E\]. Moles of A cancel leaving only moles of E left.
So would I multiply 6x10^23 by two and that would be my answer?
What units are you looking for in your answer? If the answer is to be in moles then no 2 is the answer. If the answer is supposed to be in atoms then yes you would multiply it by Avagodro's number.
the question does not specify.. just wants to know how much product. if it mentions moles in the first part then should the answer be in moles?
I would assume so.
thank you
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