0^0 is 0 or the solution doesnt exist. why??
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zero to the power of zero. equals 0 or it doesn't exist?
the answer is doesn't exist
0^0 = 1
it is equal to 1 anythng to the power of zero is 1
i need an argument why or why not.. hmmm...
yes... 0^0 in terms of a determinate is indeterminate
anything to the power 0 is 1 other than 0 itself ofcourse.. if you see the graph of x^0 it is discontinuous at x=0
0 to any power is 0 anything to the power of 0 is 1 see the conflict? So 0^0 is indeterminate
there is conflict but wouldn't that mean the theory itselt is a conflict lol?
more formally, \[\Large 0^x=0\] where x is nonzero \[\Large x^0=1\] where x is nonzero
0=1 is a false staemtn
exactly, so saying 0^0 = 1 is not correct, neither is saying 0^0 = 0
lol this question is a puzzle itself?
Ah so that is what i am telling.. it does not exist or else if we have x tending to zero then we have to evaluate the limit using the most appropriate method availbale
i guess you can see it that way, but you'll find that x=0 isn't in the domain of x^x
it is one of the seven to eight indeterminate forms.. it is a part of limits
So is your query cleared? or did it get more intensified?
Def confused, but it's ok, haha
Why are you confused??
what kind of math are you taking? like is this a college level course? because this kind of question is a little bit of a joke and yet a serious question in my ibh maths class and well, i wouldn't say there's no answer, i'd just say that it's undefined. if you graph an xˆy function, its a function of 2 variables and so it's not continuous in origin. but in the case of 0ˆ0, thinks get really messy.. i remember i asked my math teacher this question once and all he did was he looked at me and said, "because mathematicians said so."
it's a college level math course but the teacher is obviously trying to see what i'm going to answer. we have to explain why we think it's 0 or why we think there is no solution
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