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Mathematics
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OpenStudy (anonymous):
f(x)=x2+ 1x + 2
___
4
g(x)=x^3+ 1
___x^2+X
2
Find (f + g)(a).
14 years ago
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OpenStudy (anonymous):
simply add the two together in order to do this tho first you have to get the denominators to equal
14 years ago
OpenStudy (anonymous):
then replace x with a
14 years ago
OpenStudy (anonymous):
? i'm horrible at math, i can't even do that much
14 years ago
OpenStudy (anonymous):
times the bottom by 1 but using 2/2
14 years ago
OpenStudy (anonymous):
so your bottom equation is
\[\frac{x^3+x^2+x}{2}\]
correct?
14 years ago
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OpenStudy (anonymous):
if so multiply by 2/2 and you'll get
\[\frac{2x^3+2x^2+2x}{4}\]
14 years ago
OpenStudy (anonymous):
now you can add them since their denominators are the same
14 years ago
OpenStudy (anonymous):
\[(f+g)=\frac{x^2+x+2}{4}+\frac{2x^3+2x^2+2x}{4}=\frac{3x^3+3x^2+2x+2}{4}\]
14 years ago
OpenStudy (anonymous):
ok..
14 years ago
OpenStudy (anonymous):
now simply interchange x with a
14 years ago
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OpenStudy (anonymous):
\[\frac{3a^3+3a^2+2a+2}{4}=\frac{1}{4}(3a^3+3a^2+2a+2)\]
14 years ago
OpenStudy (anonymous):
since a has no given value that will be your answer
14 years ago
OpenStudy (anonymous):
ok, i keep looking it over and over to see if i understand and i am slowly getting it... thank you!.. i'm going to keep looking at it so i understand it better.
14 years ago
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