Question

under the QUADRATIC EQUATION(Roots)
If a triangle has an area of 56 sq. inches, with base of 9 inches longer that its altitude, find the length of its base.

Answer 1

if altitude means height then this is what i'd do

set the altitude as x and base as x+9

then the area is 1/2 base*hight, (1/2)*(x*(x+9)=56)
x^2+9x=108
x^2+9x-108=0
now solve for the quadratic and you get
\[x=\frac{9\pm \sqrt{513}}{2}\]