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What's the limit as x approaches infinity, (5x+8)/(10x^2+5x+2)?
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Divide top and bottom by x ... then what do you think the answer is intuitively?
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\[\lim{_x{\rightarrow}}infinity\frac{5+\frac{8}{x}}{10x + 5 +\frac{2}{x}}\]
ok, i got that and then i was able to deduce that it simplified to \[5\div(10x-5)\]
well i meant + 5
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Then by the same logic this ratio also goes to zero as x goes to infinity
oh, ok...thank ya for clarifying that
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