find the maximum and minimum distance of the point (3,4,12) from the sphere x.x +y.y+z.z=1
well i can think of a way to construct this however i'm not sure this is how it would be done
This sphere has a radius of 1. The point is √(3^2 + 4^2 + 12^2) from (0,0,0) √9+16+144 = √169 = 13 away from the origin
Therefore the min distance is 12 and the max is 14
ahh so that would be the way to solve it
That's how I'd look at it, from a pure geometrical side.
yeah that was what i wa thinking only in a sense where the center is not ,0,0,0
If the center wasn't (0,0,0) then it would make the problem harder. Still do-able, but harder.
especially if it is osmething like this|dw:1316622071864:dw|
oh wait nvm it's a a point so it would'nt be that hard
it'd still require you to do some work if the center wasn't at 0,0,0. You'd have to change the √ part to use the pythagorean theorem
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