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Mathematics 23 Online
OpenStudy (anonymous):

find the maximum and minimum distance of the point (3,4,12) from the sphere x.x +y.y+z.z=1

OpenStudy (anonymous):

well i can think of a way to construct this however i'm not sure this is how it would be done

OpenStudy (anonymous):

This sphere has a radius of 1. The point is √(3^2 + 4^2 + 12^2) from (0,0,0) √9+16+144 = √169 = 13 away from the origin

OpenStudy (anonymous):

Therefore the min distance is 12 and the max is 14

OpenStudy (anonymous):

ahh so that would be the way to solve it

OpenStudy (anonymous):

That's how I'd look at it, from a pure geometrical side.

OpenStudy (anonymous):

yeah that was what i wa thinking only in a sense where the center is not ,0,0,0

OpenStudy (anonymous):

If the center wasn't (0,0,0) then it would make the problem harder. Still do-able, but harder.

OpenStudy (anonymous):

especially if it is osmething like this|dw:1316622071864:dw|

OpenStudy (anonymous):

oh wait nvm it's a a point so it would'nt be that hard

OpenStudy (anonymous):

it'd still require you to do some work if the center wasn't at 0,0,0. You'd have to change the √ part to use the pythagorean theorem

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