Question

In the below system, solve for y in the first equation.

x + 3y = 6
2x – y = 10

Answer 1

Subtract x from both sides, then divide both sides by 3 to isolate y



\[\Large x + 3y = 6\]


\[\Large 3y = 6-x\]


\[\Large y = \frac{6-x}{3}\]

Answer 2

If you wanted to solve this system an easier way, I'd solve for y in the second equation (to avoid fractions)

Answer 3

my choices are
1/3x+2
-1/3x+6
-x+2
-1/3x+2
?

Answer 4

you can then simplify the last equation


\[\Large y = \frac{6-x}{3}\]


\[\Large y = \frac{6}{3}-\frac{x}{3}\]


\[\Large y = 2-\frac{1}{3}x\]


\[\Large y = -\frac{1}{3}x+2\]


So the answer is choice D

Answer 5

thnks so much