Question

Please help me solve this type of problem and show steps:
(6-3i)+(5+4i)
i = imaginary #

Answer 1

(6-3i)+(5+4i)


6-3i+5+4i


(6+5)+(-3i+4i)


11+i


So (6-3i)+(5+4i) = 11+i

Answer 2

just add the real parts and imaginary parts ( containing i)
= 11 + i

Answer 3

Thanks :D My math teacher told us to do distributive property... ????? What?! LOL, i dont like him, (:

Answer 4

He's basically saying that (6-3i)+(5+4i) is really

1(6-3i)+1(5+4i)


which distributes to


6-3i+5+4i