2(8u+2)=3(2u-7) 16u+4=6u-21 16u+4-6u=6u-21-6u 10u+4=(-21) 10u+4-4=(-21)-4 10u=-25 10u/10=-25/10 u=-2.5 how do i justify it
u just did
2(8u+2)=3(2u-7) 2(8(-2.5)+2)=3(2(-2.5)-7) ... replace ALL copies of 'u' with -2.5 (since u = -2.5) 2(-20+2)=3(-5-7) 2(-18)=3(-12) -36=-36 Since the last equation is true, this verifies the answer
it doesn't get any more justified than that
Unfortunately @sonofa_nh it doesn't always justify since you could be introducing extraneous solutions that do not work
well the paper says to put it in seven lines a. b. c. d. e. f. g.
does the idea make sense coraline?
eh...........no
I'm replacing all copies of the variable 'u' with -2.5 (since u is -2.5) and then evaluating like normal
at the end, I get a true equation, so u = -2.5 works
but how do i put it into seven lines?
Simple example: solve x+2=4 solution is x = 2 check: x+2 = 4 2+2 = 4 4 = 4 ... works
break up one line into two to make more lines
but what I wrote should be enough
ok i think i get it so i break up each line???
just enough to get 7 lines
a. 2(8u+2)=3(2u-7) b. 2(8(-2.5)+2)=3(2(-2.5)-7) c. 2(-20+2)=3(2(-2.5)-7) d. 2(-20+2)=3(-5-7) f. 2(-18)=3(-5-7) e. 2(-18)=3(-12) g. -36=-36
I'm basically streeeeetching it out to make it fit
thanks
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