Question

what is 6/i in standard form?

Answer 1

\[\frac{6}{i}*\frac{i}{i}=\frac{6i}{i^2}=\frac{6i}{-1}=-6i\]

Answer 2

wait why multiply by i/i?

Answer 3

easier is to memorize this relationship\[-i*i=-1\]

Answer 4

is that the conjugate?

Answer 5

you can't have i in the denominator because it is a radical by definition\[i=\sqrt{-1}\]so you are in effect rationalizing the denominator

Answer 6

k i think i get it

Answer 7

you want to make the denominator a real number, so you multiply i by itself to make it i^2 or -1 (you must do this to both numerator and denominator)

Answer 8

a-bi is the conjugate of a+bi (the complex conjugate is the imaginary part of the complex number negated)

Answer 9

k thanks

Answer 10

welcome