show that the foll: points are collinear using distance formula. A (6,2) ,B (2,-3) and C (-2,-8).Help!
colinear aint proved by distance
all point equi distance from a single point forms a circle ...
3 equal length lines can form a triangle
Thx but this problem is based on AC square = AB square +BC square.
(6,2) (2,-3) (-2,-8) -6-2 -6-2 -6-2 ------------------ 00 <-4,-5> <-8,-10> <4,5> and 2<4,5> are at least parallel
if the distance between you farthest points is equal to the distance between the sum of the distances from the end outer points to the middle point; they are in line
so you need to determine the 3 sets of distances between each point with the others. then compare the data. if the smaller numbers add up to the larger, your a straight line
its a triangle thrm all over again
Thx .formula is d= square root of (x2-x1) +(y2-y1). the pythagoras theorem.
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