If you throw a dice 6 times, what's the chance that you'd get a six on:
a: exactly one of the throws.
b: one or more of the throws.

Question

amistre64 · Answer

thats a pretty big sample space :)

anonymous · Answer

? I don't understand what your saying... lol

amistre64 · Answer

1 6 15 20 15 6 1

neither do i yet :)

anonymous · Answer

a. (1/6)*(5/6)^5*6 = (5/6)^5
b. (5/6)^6

anonymous · Answer

LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)

anonymous · Answer

er, b. 1-(5/6)^6

amistre64 · Answer

P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6

amistre64 · Answer

P(6) = 1/6; P(/) = 5/6

anonymous · Answer

Thanks!

amistre64 · Answer

satellite is good at these, he does them instead of the crosswords during breakfast :)

anonymous · Answer

exactly one:
$$\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5$$

amistre64 · Answer

he has rooms filled with unthrown dice just waiting to be explored lol

anonymous · Answer

they are thrown.

anonymous · Answer

since 6 choose 1 is 6, this answer is really
$$(\frac{5}{6})^5$$

anonymous · Answer

Dang! I didn't think I would get so much attention :P

anonymous · Answer

one or more throws means not no sixes.  the probability  you get no sixes is 
$$(\frac{5}{6})^6$$ so your answer is 
$$1-(\frac{5}{6})^6$$

anonymous · Answer