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Show by means of an example that lim x-> a [f(x)g(x)] may exist even though neither lim x-> a f(x) nor lim x -> a g(x) exists.
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Stewart Calculus?
I assigned this problem this semester ;)
Any chance you know the answer?
yes
many answers
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infinity many
one example will do :)
you cannot count them on your fingers and toes is as much as i know so therefore it is many and possibly infinitely many
lol
never mind I got one I think
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f(x)=1+sqroot(x) and g(x)= 1 - sqroot(x) when a <0?
Think of something really simple.
How about this function f(x) = 0, for x =< 0 1, for x > 0 You should be home free now.
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