Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Show by means of an example that lim x-> a [f(x)g(x)] may exist even though neither lim x-> a f(x) nor lim x -> a g(x) exists.

OpenStudy (zarkon):

Stewart Calculus?

OpenStudy (zarkon):

I assigned this problem this semester ;)

OpenStudy (anonymous):

Any chance you know the answer?

OpenStudy (zarkon):

yes

myininaya (myininaya):

many answers

OpenStudy (zarkon):

infinity many

OpenStudy (anonymous):

one example will do :)

myininaya (myininaya):

you cannot count them on your fingers and toes is as much as i know so therefore it is many and possibly infinitely many

myininaya (myininaya):

lol

OpenStudy (anonymous):

never mind I got one I think

OpenStudy (anonymous):

f(x)=1+sqroot(x) and g(x)= 1 - sqroot(x) when a <0?

OpenStudy (jamesj):

Think of something really simple.

OpenStudy (jamesj):

How about this function f(x) = 0, for x =< 0 1, for x > 0 You should be home free now.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!