Question

explain how to Differentiate f(x)=-5x(2X-3)^4

Answer 1

the form is off...

Answer 2

are you asking -5x * 2 * -3^4

Answer 3

if so... -3^4 is 81... times 2 is 162.. times -5 is -810

Answer 4

im asking to find the derivative of\[-5x(2x-3)^{4}\]

Answer 5

but I doubt that is what your looking for...

Answer 6

product rule with the differentiation of one being the chain rule

Answer 7

chain rule... exactly

Answer 8

a'b + b'a

Answer 9

\[-5x*(2x-3)^4\]

Answer 10

so start out by dividing the two up... -5x and (2x-3)^4

Answer 11

call them a and b

Answer 12

u = -5x
v = (2x-3)^4
v' = 8(2x-3)^3
u' = -5

the chain/product rule is:

uv'+vu'

just attached the givens,

:))

Answer 13

kumar is correct..

Answer 14

multiply the u and v', then the u' and v, then add the two...

Answer 15

haha i'm afraid to foil the parenthesis lmfao

Answer 16

that would be ugly...

Answer 17

Dannibe, do you understand?

Answer 18

oh yes it would

Answer 19

no i can't get the right answer

Answer 20

=]

Answer 21

actually the 4 wouldn't be cubed

Answer 22

the answer is supposed to be \[-5(2x-3)^{3}(10x-3)\]

Answer 23

so your starting with -5(2x-3)^4 - 40x(2x-3)^3 ?

Answer 24

i dont see this equation simplifying to that.. but let me check

Answer 25

Thats where I got to. how would you work it after that point?

Answer 26

ahhhh

Answer 27

devide the whole line by (2x-3)^3

Answer 28

pull that to the front..

Answer 29

the you have (2x-3)^3 * (-5 - 40x*(2x-3))

Answer 30

distribute the 40x*(2x-3)

Answer 31

err.... start with -5(2x-3)^4 - 40x(2x-3)^3

Answer 32

then go to -5(2x-3)^3 * (1-8x)

Answer 33

look like I fooked it up... reworking

Answer 34

ok.. the anwser is correct..

Answer 35

here is how you get there...

Answer 36

start with -5(2x-3)^4 - 40x(2x-3)^3
factor out -5(2x-3)^3
then you get -5(2x-3)^3 * (2x - 3 + 8x)

Answer 37

hence your anwser