Question

an electron in cathode-ray tube accelaerates from a sped of 2.00*10^4 m/s to 6.00*10^6 m/s over 1.50 cm
a) in what time interval does the electron travel this 1.50 cm ?

Answer 1

you want algebra or calculus?

Answer 2

phesics

Answer 3

physics

Answer 4

assuming a uniform acceleration?

Answer 5

brb.. need a beer to find the equation..

Answer 6

wouldn't it just be

a=d/t

Answer 7

thats what im thinking...

Answer 8

seems a little cheezy for physics..

Answer 9

yea then solve for "t" is what i'm thinking also

Answer 10

but it's got big words in there!

Answer 11

ahh
d=v0t+1/2at^2

Answer 12

thats the guy my beer was searching for..

Answer 13

vf^2-v0^2 = 2ad

Answer 14

xf=xi + 1/2(vxi+vxf)t

Answer 15

use that last one to solve to a
1.2e15

Answer 16

then vf-v0=at to solve for time

Answer 17

i got 4.98e-9 seconds