The diameter of a circle is 16cm By what amount must the radius be decreased in order to decrease the area by 48pi square centimeters. (i have to solve it using applications of equations)
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OpenStudy (anonymous):
area = pi*d/4
OpenStudy (anonymous):
area = pi*(d^2)/4
OpenStudy (anonymous):
sry...
OpenStudy (anonymous):
how did you get this?
OpenStudy (anonymous):
that is just the equation for the area of a circle..
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OpenStudy (anonymous):
so to decrease the area...
OpenStudy (anonymous):
i understand that, but how do i get waht number the radius decreases by?
OpenStudy (anonymous):
two equations
OpenStudy (anonymous):
area = pi*(16^2)/4
area -48pi = pi*(16^2)/4
OpenStudy (anonymous):
pi*(256/4)-48pi
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OpenStudy (anonymous):
area -48pi = 64pi - 48 pi
OpenStudy (anonymous):
area - 48pi = 16pi
OpenStudy (anonymous):
16pi is your answer
OpenStudy (anonymous):
ugh im so confused :( i wish my teacher would acctually teach me stuff
OpenStudy (anonymous):
ok.. so lets backup
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OpenStudy (anonymous):
grab a beer.. lets go...
OpenStudy (anonymous):
start with the equation of a circle
OpenStudy (anonymous):
area = pi (d^2/4)
OpenStudy (anonymous):
X 2 + Y 2=r2?
OpenStudy (anonymous):
now, both side are in "area" units...
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OpenStudy (anonymous):
yes, that is the equation of a circle.. i meant the equation for the area fo a circle..
OpenStudy (anonymous):
area = pi (d^2/4)
OpenStudy (anonymous):
oh A= pi(r2)
OpenStudy (anonymous):
start with that guy
OpenStudy (anonymous):
yeah we can use that one too
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OpenStudy (anonymous):
area = pi * r^2
OpenStudy (anonymous):
subtract from both side the area you want to change
OpenStudy (anonymous):
so A= pi(8^2)
OpenStudy (anonymous):
area -48pi = pi (8^2)-48pi
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
oh i get since we know the area we put it out front
OpenStudy (anonymous):
kinda.. we know what area we want to subtract... to we can put that on both sides of the equation without changing anything
OpenStudy (anonymous):
so break down that equation...
OpenStudy (anonymous):
area -48pi = 64pi -48pi
OpenStudy (anonymous):
then add thos together to get 16pi?
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
then add 48 to both sides?
OpenStudy (anonymous):
now what radius gives you 16pi
OpenStudy (anonymous):
4
OpenStudy (anonymous):
pi r^2
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OpenStudy (anonymous):
sqrt of 16 is 4
OpenStudy (anonymous):
easy peasy
OpenStudy (anonymous):
oh okay thanks i get it
OpenStudy (anonymous):
although im not sure how to put that in the way she wants us to write it
OpenStudy (anonymous):
that was always my problem too... i got the answers... just the work was never there..