-Under the Quadratic equation (ROOTS)
Determine the possible values of k so that the roots of 4x^2kx+35=0 differ by 1

Question

anonymous · Answer

Is there meant be be a plus or a minus before the kx?

anonymous · Answer

yes that was what i was going to ask too!!

anonymous · Answer

If there isn't, I'm way out of my league :P

anonymous · Answer

Anyway, you'll end up with something along the lines of $$x=\frac{-k \pm \sqrt{k^2-c}}{8}$$, and you need to say that the difference between the two roots (two because of the $\pm$ sign) is 1. That should let you find k.

anonymous · Answer

$$4x^2kx+35=0 $$

anonymous · Answer

that's the equation

anonymous · Answer

I see no way of solving it in that case!

anonymous · Answer

I feel there is a misprint in yr book. it shud be + kx + 35

anonymous · Answer

ur ryt..
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anonymous · Answer

there is a  plus sign b4 the kx

anonymous · Answer

let me check now......

anonymous · Answer

sorry, can't seem to get it right....☺

anonymous · Answer

let the two roots be alpha and beta

 alhpha + beta = -k/4 

(alpha)(beta)=35/4 

(alpha + beta ) ^2 = ( alpha - beta )^2 + 4(alpha)(beta) 

k^2/16 = 1+35 

k^2 = 36(16)

 k = 6* 4 = 24

anonymous · Answer

is my anwer correct
?

anonymous · Answer

yes Abhinav yr ans is correct !!
Congrats n a medal ...☺