Question

Question is in the picture below. I dont know the equation asked. Do you?

Answer 1

it wants h...but i have no idea what equation its going to be lol

Answer 2

anyone?

Answer 3

you gotta to use some formulas

Answer 4

like? lol

Answer 5

..................

Answer 6

?

Answer 7

it has to be material specific i assume.

but in general; the height is equivalent to the position function that is parabolic in nature. and you subtract the height from the base function to arrive at an equation that will model the actions

Answer 8

\[h(t)=-\frac{1}{2}g\ t^2+V_i\ sin(\theta)\ t +H_i - h = 0\]

Answer 9

so thats h? lol

Answer 10

we can try to modify it by more by addressing the Vi cos(a) t as well to determine a distance covered in the time alooted.

\[V_i\ cos(\theta)\ t=d \]
\[t = \frac{d}{V_i\ cos(\theta)}\]
and introduce this into h(t):

\[-\frac{1}{2}g\ (\frac{d}{V_i\ cos(\theta)})^2+V_i\ sin(\theta)\ (\frac{d}{V_i\ cos(\theta)}) +H_i - h = 0\]

\[-\frac{d^2g}{2V_i}sec^2(\theta) +\frac{dV_i\ sin(\theta)}{V_i\ cos(\theta)} +H_i - h = 0\]

\[-\frac{d^2g}{2V_i}(tan^2(\theta)+1) +d\ tan(\theta) +H_i - h = 0\]


\[-\frac{d^2g}{2V_i}tan^2(\theta) +d\ tan(\theta) +\left(H_i - h -\frac{d^2g}{2V_i}\right)= 0\]

Answer 11

its just asking for the equation for h..i dont think its asking for the answer

Answer 12

was it the first equation you wrote? should i try that one?

Answer 13

..... i would have stopped at the first equation if i thought so lol

Answer 14

this last equation is everything we need; and its easily solved for h, and we might as well assume that the initial height, or H1, is 0

Answer 15

ill try it!

Answer 16

\[h = -\frac{d^2g}{2V_i}tan^2(\theta) +d\ tan(\theta) -\frac{d^2g}{2V_i}\]

Answer 17

or to be consistent with the picures ...

\[h = -\frac{d^2g}{2V_i}tan^2(\theta_i) +d\ tan(\theta_i) -\frac{d^2g}{2V_i}\]

Answer 18

ill do my best lol..lets see if it works

Answer 19

says its wrong

Answer 20

oh, its right, its just not the answer they are looking to compare it against; which is why its source specific and not a general answer that you can derive through mathing it out.

Answer 21

lol i tried again and it said no

Answer 22

if you can find any fault in the math, be my guest :)