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Chemistry 15 Online
OpenStudy (anonymous):

can sum1 plz help with this question.. write the correct formula for Li2O

OpenStudy (anonymous):

\[Li _{2}O\] that is the correct formula... if you want the name it's lithium oxide

OpenStudy (anonymous):

it is still Li(subscript 2) O. lithium oxide

OpenStudy (anonymous):

Yes. This is calculated by the charges since it is an ionic compound. \[Li ^{+} O ^{2-}\] You need two Li to cancel the charge of one O

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