Question

X^2+6x-27=0

Answer 1

3,-9

Answer 2

Yes, but why? Giving the answer isn't very helpful.

Answer 3

first you need to factor 27
into two numbers the sum or difference of which makes 6

Answer 4

I don't understand how to do it

Answer 5

use quadratic root formula

(-b (+-) sqrt(b^2-4*a*c)) / 2a

one solution is + sqrt, other solution is - sqrt

Answer 6

so in this case you would have
(-6 + sqrt(36-4*1*(-27)) / 2
and
(-6 - sqrt(36-4*1*(-27)) / 2

Answer 7

you can either use the quadratic formula or do it with factoring.
have you studied / done any of these before ?

Answer 8

no

Answer 9

has your teacher talked about the quadratic equation or factoring ?
not sure which method your teacher wants you to use here.

Answer 10

You can also tell the type of roots you will get by evaluating the discriminant (the part under the radical):
(b^2 - 4*a*c)

If discriminant < 0, you will get two complex roots.
If discriminant > 0, you will get two real roots.
If discriminant = 0, you will get two equal (real) roots

Answer 11

(and if the discriminant is a perfect square then the two roots are rational numbers)

Answer 12

???? she says solve for x

Answer 13

well, you can either use the quadratic formula (as deezil showed above)

or (if you are not suppsed to use the quadratic formula) do factoring -
which is explained here:

http://www.purplemath.com/modules/factquad.htm

Answer 14

thanks :-)