Question

My professor gave me this code to work with...
struct node{
char value;
struct node * nPtr; //points to next node
};
typedef struct node nodePtr;
typedef nodePtr * listNodePtr;

And to implement this function
void insert(listNodePtr *ptr, char c)

When I compile this in gcc, I get this
prelab4.h:7: error: expected â)â before â*â token

Why is it telling me this? I feel like putting a ) after the * wouldn't be good.

Am I accessing it correctly? I am calling for a pointer of type listNodePtr, right?

Answer 1

Hmm, I'm not sure why you are getting that error, but are you sure insert should be taking listNodePtr* (which is equivalent to struct node**) instead of listNodePtr (which is struct node*)

Also, you might be missing a semicolon after the void insert declaration:

void insert(listNodePtr *ptr, char c);

If that doesn't help, could you paste the entirety of the header to a site like pastebin or something?

Answer 2

I literally copied and pasted this from the prelab. I have no clue why it won't compile. I've attached out prelab form. I feel like I should brush up on some linkedlist stuff, and this should make sense, but I have no idea why they would give us bad code to begin with!!

Answer 3

The code below compiles.

#include <stdio.h>

struct node{
char value;
struct node * nPtr; //points to next node
};
typedef struct node nodePtr;
typedef nodePtr * listNodePtr;


//void insert(listNodePtr *ptr, char c)

int main (int argc, char * const argv[])
{
printf("hello world");
}