Question

You are a student who plans to attend the amusement park for two days. This will be fun! Now it's time to figure out the cost. You won a coupon for 50% off a 1-day pass but it cannot be combined with other offers. The amusement park also offers a $5 student discount; however, you cannot get the $5 student discount off the 2-day pass. Use the information in the chart above to determine which option is the better deal.
• Option 1: Buying a ticket at 50% off today and then purchasing a new 1-day ticket at the student price tomorrow.
• Option 2: Buying a 2-day pass and not using the coupon at all.

Answer 1

someone please help i feel so lost!!!

Answer 2

is there a missing chart?

Answer 3

1 day at the park for $44.95
2 days for $71.95
3 days for $94.95

Groups of 10 pay $400.00 for 1-day tickets.
A family with 2 adults and 3 children under 12 will pay only $174.45 for 1-day tickets.
Student discounts are $5.00 off for 1-day tickets.
Coupons of 50% off admission cannot be combined with any other offer.

Answer 4

thts tha chart sorry

Answer 5

Option 1: .5(44.95) + (44.95-5) = $62.425
(half price on the first day + $5 off on the second day)

Option 2: $71.95
(two day pass from the table)

obviously option 1 is the better deal

Answer 6

more questions based on this scenario?

Answer 7

yes

Answer 8

A business wants to give each of its employees a free ticket to the amusement park and has budgeted $1200 for tickets.
1. Write and solve an inequality to find the maximum number of 1-day, adult tickets that can be bought. When you round your answer, remember that there is no such thing as "part" of a ticket.



how do i do tht?

Answer 9

i kno i saw i apologize i didnt see it thts y i deleted tha comment

Answer 10

ok no prob

Answer 11

idk how to do inequalities :/ so how wud i go about doing the thing i just sent

Answer 12

if n is the number of 1-day tickets purchased, then solving the inequality\[44.95n \le1200\] for n (rounding down to the next lower integer) will give the max number of tickets that can be purchased without exceeding $1200. solving you would get\[n \le \frac{1200}{44.95} \approx 26.69\]therefor the max number of tickets that they can purchase is 26 tickets.

Note: 26 tickets times $44.95 = $1168.70 and if they try to buy one more they would exceed the $1200 spending cap: 1168.70 + 44.95 = $1213.65, which confirms the 26 tickets max

Answer 13

O.o woah....

Answer 14

make sense?

Answer 15

ummm...honestly..?

Answer 16

ummm...honestly..?

Answer 17

no, please lie

Answer 18

haha im just playn yea it makes sense

Answer 19

me too :)

Answer 20

mo' questions?

Answer 21

:D

Answer 22

nope ure awesome for helping me

Answer 23

i was happy to do it... later

Answer 24

peace