Question

Can someone remind me how to write an equation for a line parallel to an equation and containing a certain point?

Answer 1

same slope

Answer 2

eg
y = 3x + 1 is parallel to
y= 3x - 4

Answer 3

What do you do to make the point show up on the line?

Answer 4

like... 3x+y=5, and you need an equation with the same slope (3x) that also contains the point (-6,4)

Answer 5

use the general form

y-y1 = m(x-x1) where m= slope and the point is x1,y1

3x + y = 5
rearrange to slope/intercept form:
y = -3x + 5 - the slope is -3
so plug in (-6,4):

y-4 = -3(x - -6)

y -4 = -3x -18
y = -3x - 14 is the required equn.