How does x^2 + y^2 = 4x give the equation of a circle?
subtract 4x from both sides, then solve for y. this should give you the formulas for the upper and lower semicircle
not exactly you'll have to complete the square
well, yeah you can do that do
if you subtract -4x you'll get 0=y^2+x^2-4x... if you complete the square you'll get \[y^2+x^2-4x+4=4\] \[=y^2+(x-2)^2=4\] you can go farther if you'd like but you don't need to divide by 4 and you'll get the 1 by itself which is considered another equation of a circle
\[=\frac{y^2}{4}+\frac{(x-2)^2}{4}\]
=1
Is completing the square the only otion it seems?
i believe so or you can do it the way that lagrange said but i think what they call his is Cartesian and it gives two semi circles which complete the circle
Oh ok thanks!!
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