Question

sqrt(2x+1)-sqrt(x)=1. Solve for x.

Answer 1

x=0

Answer 2

x = 0 and x = 4

Answer 3

first square both sides u will get

2x + 1 + x + 2 ( sqrt x(2x+1)) = 1

so it will be

3x = -2 ( sqrt x(2x+1))

again square on both sides

9 x^2 = 4x(2x + 1)

u willl get

9x = 8x + 4

x = 4

Answer 4

since will cancel out x between the steps u can consider x =0 also

Answer 5

the answer is 0 and 4. how can i solve?

Answer 6

hey i gave u the solution right?

Answer 7

\[\sqrt{2x+1}-\sqrt{x}=1\quad,\quad x\geq 0\]\[\sqrt{2x+1}=\sqrt{x}+1\]\[2x+1=x+1+2\sqrt{x}\]\[x=2\sqrt{x}\]\[x(x-4)=0\quad,x=0\vee x=4\]