how do i find the inverse of h=radical 3s over 2????

Question

hoybaby · Answer

$$h=\sqrt{3s}\over 2$$

anonymous · Answer

$$ 2/\sqrt{3s}$$

hoybaby · Answer

what? how did you get that?

anonymous · Answer

that's if your question is about the multiplication inverse of h

hoybaby · Answer

the two is not diving the h just the $$\sqrt{3}$$

hoybaby · Answer

i have to write the formla so that the height is the input and the legth of the sides is a output which means the inverse

anonymous · Answer

ok

anonymous · Answer

$$=\sqrt{3s}/2  ====> 2h=\sqrt{3s} ===> 4h^{2} =3s ====> s =4h^{2}/3$$

hoybaby · Answer

where do you get the 4 from?

anonymous · Answer

$$s=4h^{2} /3$$

anonymous · Answer

squaring both sides will give
$$3s =4h^{2}$$

anonymous · Answer

then divide both sides on 3
$$s=4h^{2}/3$$

anonymous · Answer

the idea is to take the s out of the radical by squraring both side

hoybaby · Answer

ok i think i see it much clearer now. care to help me with other problem i have?

anonymous · Answer

ok

hoybaby · Answer

$$h=0.8(200-A)$$
uf biwlers average is over 200 the handicap is 0. rewrite it so average is output and handicap in input. if your handicap is 32, whats your average?

anonymous · Answer

$$h=0.8(200-A)$$
$$h =160 -0.8 A$$
$$0.8 A=160 - h$$
$$A=(160-h)/0.8$$
when h=32 ===> A =(160-32)/0.8 = 
160

hoybaby · Answer

if my handicap is 32, will that make my average be 134.4?

anonymous · Answer

let me check again

anonymous · Answer

I got 160