Question

Find n such that the error in the approximation of the definite integral is less than .00001 using the trapezoidal rule.

Answer 1

∫011÷(1+x)dx

Answer 2

sorry! thats the integral from 0 to 1 of 1/(1+x)dx

Answer 3

I just don't know how to use the max / abs value part of the formula

Answer 4

the integral from 0 to 1 of 1/(1+x)dx
f(x)=1/(1+x), f '(x)=1/(1+x)^2, and f ''(x)=2/(1+x)^2, f ''(0)=2/(1+0)^2=2
now
10^-5 <[(1-0)/12]h^2 M, M=2, but h=1/n,
[1/12](1/n)^2 M <10^-5
1/(6n^2)<10^-5
10^5 /6< n^2
sqrt(10^5 /6)< /n/
129.1<n
use n=130 and beyond answer