Question

Solve algebraically. Clearly define all variables, write an appropriate equation, and solve. One number is 6 more than twice the other number. If the sum of the two numbers is 24, find the two numbers.

Answer 1

One Number must be 6 more than twice the number and in your case a is your one number

Answer 2

doesn't fit the above statment

Answer 3

I thought i was going crazy satellite, or am I? lol

Answer 4

6=b
18=a

Answer 5

let's call the the first number n
then the other one is 6 more than twice the first one, in other words 2n+6

Answer 6

^ those answers are correct

Answer 7

equations would be
A=2b+6
A+B=24

Answer 8

and their sum is 24. so you know that
\[n+2n+6=24\]

Answer 9

making
\[3n+6=24\]
\[3n=1\]
\[n=3\]

Answer 10

oops, should be
\[3n=18\]
\[n=3\]

Answer 11

and you can see that there is clearly more than one way to solve this problem. you can use two variables, or you can use one variable

Answer 12

n=6 heheh

Answer 13

XD

Answer 14

details details...

Answer 15

also please notice that we could have said one number is n and the other is 24 - n
and so
\[24-n=2n+6\]

Answer 16

in other words you have many ways to solve one problem. use two variables, one variable, solve for one in terms of the other in two different ways. the only way you can make a mistake is to divide 18 buy 3 and get 3