Question

(4r+5)2>or equal to 6r

Answer 1

8r + 10 >or equal to 6r
-8r -8r
10 >or equal to -2r
/2 /2
5 >or equal to -r
*-1 *-1
-5<or equal to r

Answer 2

8r+10>or=6r
2r>/=-10\[r \ge-5\]

Answer 3

r<or=-5 thank you

Answer 4

I think r has to be equal to or greater than -5.

Answer 5

when there's a negative number the sign must be reverse

Answer 6

We both came up to that conclusion, how did you turn it around so that r is less than or equal -5?

Answer 7

the inequlatity sign must be reverse

Answer 8

the -r is less than the 5, so you multiply by -1 to make the positive r greater than -5

Answer 9

thank you damonky,

Answer 10

Only if the equation was multiplied or divided by a negative number. In my solution I divided thru by a POSITIVE 2. To double check, substitute a test number. You say r must be less than -5, so let r=-6 and substitute in orig equation.

(4(-6)+5)2 > or equal 6(-6)
(-24+5)2 > or = -36
(-19)(2)>or equal -36
-38 > or = -36

Don't think so

Answer 11

Thanks for the check Radar.....

Answer 12

From Mathematica:\[\text{Reduce}[(4r+5)2\text{$>$=} 6r] \to r\geq -5 \]