Determine the type and number or roots for the following. 3x^2+x-1=0
For: ax^2+bx+c=0 Calculate the discriminant of the quadtratic equation: b^2-4ac Then check it's value: if it's < 0 --> there will be no real roots if it's = 0 --> there will be one real root if it's > 0 --> there will be two real roots if it's a perfect square --> two real roots, which are rational numbers
IS this the formula or is this the answer? I have never done this before so I am not fimiliar with it.
OK In general, you have this representation of a quadratic: ax^2+bx+c=0 In your case it's: 3x^2+x-1=0 So: a=3 b=1 c=-1 Now, calculate the discriminant value using the values above for a,b,c: b^2-4ac what do you get ?
?
you are told that a=3 , b=1, c=-1 How much is: b^2-4ac=? Do you know how to do this ?
13
correct !
now what do I do?
Check the discriminant value: if it's < 0 --> there will be no real roots if it's = 0 --> there will be one real root if it's > 0 --> there will be two real roots if it's a perfect square --> two real roots, which are rational numbers you know the discriminant value is 13. so look at the above and you will know the information about the roots which the question is asking about.
So this is saying that there will be no real roots?
well, 13 is greater than 0 - right ? so look at the one that says: if it's > 0 --> ....
so there will be two real roots
yes that's right. now is 13 a perfect square or not ?
no because it is prime
good - so you also know that the roots are not going to be rational numbers.
right
now here's the full quadratic equation: First, we have the discriminant, which you already calculated, and is 13 in our example. \[\Delta=b^2-4ac\] Now the roots will be: \[x _{1,2}=\frac{-b \pm \sqrt{\Delta}}{2a}\]
What is the x1,2
now you can see that the discriminant is placed inside a square root. All these properties of the discriminant are a result of this. if it's < 0 --> there will be no real roots if it's = 0 --> there will be one real root if it's > 0 --> there will be two real roots if it's a perfect square --> two real roots, which are rational numbers
|dw:1316836161219:dw|
Join our real-time social learning platform and learn together with your friends!