Question

Find the polynomial f(x) that has the roots of –2, 3 of multiplicity 2. Explain how you would verify the zeros of f(x).

Answer 1

please help?

Answer 2

please?

Answer 3

\[(x+2)^2(x-3)^2\]

Answer 4

multiplicity 2 than root is bound

Answer 5

\[as( x) \rightarrow \infty, y \rightarrow \infty\]
\[as(x)\rightarrow-\infty, y \rightarrow \infty\]

Answer 6

well if u mean only 3 has the multiplicity 2 then it would be (x+2)(x-3)^2.
If both are multiplicity 2 then it would be (x+2)^2 X (x-3)^2.
u verify the zeroes by taking each thing under the parenthesis to zero so
x+2 =0 and x-3= 0 so isolate x and we got
x=-2 and x=3

Answer 7

maybe only 3 has mult of 2
x+2)(x-3)^2

Answer 8

f(x)= (x+2)(x-3)^2
f(x)= (x+2)(x-3)^2=0
x+2=0, x=2 and
(x-3)^2=0, x=3 and 3