Question

I have to do improper integral comparison. What is larger than e^x / sin (x/2)?

Answer 1

Your answer makes little sense, but remember sin is bounded.

Answer 2

I apologise for not explaining it properly. My English has gone a little bit rusty, but your answer might actually prove to be useful. I'll use your advice and I'll see how it goes..

Answer 3

\[\int\limits_{0}^{1} (e^{x})/(\sin(x/2))\]

Answer 4

\[=\lim_{t\rightarrow0^+}\int_t^1{\frac{e^x}{\sin(\frac{x}{2})}}\]

Answer 5

To use the comparison theorem, select an easier function like \[\frac{1}{\sin(x)}\]

Answer 6

Thank you, agdgdgdgwngo! :)

Answer 7

since that easier function is divergent on the interval (0, 1], then the original function is also divergent