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integration of (1+e^x)^2 /e^x
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expand the top, divide out the denominator and see what we got left?
\[\int\limits_{a}^{b} ((1+e^x)^2)/e^x \] hmmm... long time since Cal II. Maybe Integration by Parts?
\[\int \left(e^{-x} + e^{x} + 1 \right)dx = -e^{-x} + e^x + x \]
\[\int\frac{(1+e^x)^2}{e^x}dx\] \[\int\frac{1+2e^x+e^{2x}}{e^x}dx\] \[\int\frac{1}{e^x}+\frac{2e^x}{e^x}+\frac{e^{2x}}{e^x}dx\] \[\int e^{-x}+{2e^x}+{e^x}dx\]
typoed myself lol
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\[\int e^{-x}+2+{e^x}dx\] as i see it
yup it should be 2 sorry my bad ..amistre is right
Whoops I made a mistake.
my brain did it right, and my fingers argued with me lol
so the final answer is \[-e^-x+2x+e^x ?\]
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