Question

What does it mean to verify Ohm's Law? I measured the total voltage of 3 resistors in series and also the V_1, V_2 and V_3 at each of the resistors. I also measured the current in the circuit

Answer 1

So I have the measured current value, do I compare it with the theoretical current value by going total voltage / sum of three resistors?

Answer 2

Or do I find the current at each resistor add them and divide by 3?

Answer 3

Theoretical current would be (total voltage)/(total resistance).

You could also find the theoretical voltage drop across each resistor from V=iR

Answer 4

Yes, but I was wondering which total voltage I take, the total voltage I measured in the circuit the sum of the voltage values at the 3 resistor

Answer 5

the DMM also has uncertainties thats why it could be different?

Answer 6

I meant or the sum of the voltage values at the 3 resistor

Answer 7

The total voltage should be equal to the sum of the voltages. If they are different because of the uncertainties then use the measured total voltage, it should be a little more accurate.

Answer 8

thank you they are different by 0.0007 but within accuracy range

Answer 9

for adding resistors each as an uncertainty too would I add up the uncertainty

Answer 10

Yes, the uncertainties would add

Answer 11

Okay that make sense I'm just slightly confuse b/c the dmm has an uncertainty and the resistor has a tolerance